Question

find the smallest square number that is divisible by each of the numbers 8,15and20
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Answer 1

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$\bold{\longmapsto}$The number that is perfectly divisible by each of the numbers 8, 15, and 20 is their LCM. Here, prime factors 2, 3, and 5 do not have their respective pairs. Therefore, 120 is not a perfect square. Therefore, 120 should be multiplied by 2 × 3 × 5, i.e. 30, to obtain a perfect square.

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Answer 2

hope it helps............