Question

find the smallest square number that is divisible by each of the numbers 4,8 and 5 ​

Answer 1

Answer:

Step-by-step explanation:

Smallest square  number divisible by 4, 8. 5 = LCM of 4,8,5

LCM of 4,8, 5 is

4 |4, 8 , 5

2|1, 2, 5

5|1, 1 , 5

  |1 , 1 , 1  

Thus LCM is 4 * 2 * 5 = 40.

Check if 40 is a perfect square.

2|40

2|20

2|10

5|5

 |1

Thus factors of 40 are 2 * 2 * 2 * 5

As we can see 2 and 5 donot occur in perfect pairs and hence 40 is not a perfect square.

Now we should make 2 and 5 in perfect pairs

thus our number becomes

40 * 2 * 5  = 2 * 2 * 2 * 2 * 5 * 5

400 =  2 * 2 * 2 * 2 * 5 * 5

Now it becomes a perfect square.

Thus the smallest square number is 400.

Answer 2

ANSWER:

400

STEP BY STEP EXPLAINATION:

LCM of 4,8 and 5 is 40.

40= 2×2×2×5

But 40 is not a square number because only 2×2 is in pair, the left out 2×5 is not in pair.

So to make it a perfect square, we need to multiply it by 2×5.

So the multiple of 40, which is a square number is 40×2×5= 400. So your answer is 400 .

Hope it's correct.

Have a good day.