Question

find the smallest square number that is divisible by each of 6,9 and 15​

Answer 1

step 1: Find the LCM of 6, 9 and 15

6 = 3 × 2

9 = 3 × 3

15 = 5 × 3

Here, only 5 and 2 are not in pairs.

LCM = 90

step 2: Multiply the numbers which are not in pair to the LCM

90 × 2 × 5 = 900

∴ The square number is 900

• 900 is the square of 30

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