Question

Find the smallest square number that is divisible by each of the numbers 18, 20, 24 and 27.
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Answer 1

Answer:

32400

Step-by-step explanation:

Firstly, let's try to take out the L.C.M of the numbers.

Then we get a set of prime numbers after finding the LCM of 18, 20, 24 and 27, multiplying these prime number will give us the LCM of 18, 20, 24 and 27, but we need to find the lowest square. Therefore, Then we try to check whether they can be arranged in pairs. As I got 2 × 3 × 5 which is unpaired, we try to multiply the whole LCM with 2 × 3 × 5 (I.e. we multiply it with 30). Then we get the lowest square which is divisible by 18, 20, 24, and 27.

For reference, I have provided a note above.

I know, my handwriting is not too good, but I still hope it helps.

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