Find the smallest square number that is divisible by each of the numbers 2, 3and 4.
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L.C.M. of 8, 15 and 20 is 120.
Prime factors of 120 = 2 x 2 x 2 x 3 x 5
Here, prime factors 2, 3 and 5 have no pair. Therefore 120 must be multiplied by 2 x 3 x 5 to make it a perfect square.
\therefore120\times2\times3\times5=3600
Hence, the smallest square number which is divisible by 8, 15 and 20 is 3600.
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