Math, asked by balavasanthimm, 23 days ago

Find the smallest square number that is divisible by each of the numbers 12, 15 and 21.

Answers

Answered by Anonymous
7

Answer:

420

Step-by-step explanation:

Solution:-

If we want to find the smallest number to be divided by such numbers we have to find LCM.

 \begin{array} {c| l}2&12,15,21 \\ \hline 2& 6,15,21 \\ \hline 3&3,15,21 \\  \hline5&1,5,7 \\  \hline7&1,1,7 \\ \hline &1,1,1 \end{array}

So, LCM = 2 × 2 × 3 × 5 × 7 = 420.

Answered by sushanthakur2118
0

Answer:

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