Find the smallest square number that is divisible by each of the numbers 8, 15 and 20. LCM method can't work. another correct method will be selected as brainliest. can anyone answer?
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Step-by-step explanation:
Let us find LCM of 8,15 and 20
8=2×2×2
15=3×5
20=2×2×5
So, LCM =2×2×2×3×5=120.
For nos which are not in pairs in LCM factors, we need to multiply 120 by 2, 3 and 5 to make it a perfect square.
Required Number =120×2×3×5=3600
Answered by
1
Answer:
12× 8
= 96
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hope it your help ok
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