Math, asked by yadavprathmesh01, 3 days ago

Find the smallest square number that is divisible by each of the numbers 8, 15 and 20. LCM method can't work. another correct method will be selected as brainliest. can anyone answer?​

Answers

Answered by ashishrockspj
0

Step-by-step explanation:

Let us find LCM of 8,15 and 20

8=2×2×2

15=3×5

20=2×2×5

So, LCM =2×2×2×3×5=120.

For nos which are not in pairs in LCM factors, we need to multiply 120 by 2, 3 and 5 to make it a perfect square.

Required Number =120×2×3×5=3600

Answered by legendrohit002
1

Answer:

12× 8

= 96

please mark me a Brain list please

hope it your help ok

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