find the smallest square number that is divisible by each of the 8,15 and 20.
Answers
Answered by
1
Answer:
3600
L.C.M. of 8, 15 and 20 is 120. Here, prime factors 2, 3 and 5 have no pair. Therefore 120 must be multiplied by 2 x 3 x 5 to make it a perfect square. Hence, the smallest square number which is divisible by 8, 15 and 20 is 3600.
Answered by
1
Answer:
3600
Step-by-step explanation:
8,15 and 20 LCM is 120 and prime factor 2,3 and 5 has no pair so, we have to multiply 120 with 2*3*5 we get 3600
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