Find the smallest square number that is divisible the smallest square number that is divisible by each of the numbers 12, 15 and 21.visible by each of the numbers 12, 15 and 21.⊕
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Step-by-step explanation:
hlo mate here's your answer
Solution:
L.C.M. of 8, 15 and 20 is 120.
Prime factors of 120 = 2 x 2 x 2 x 3 x 5
Here, prime factors 2, 3 and 5 have no pair. Therefore 120 must be multiplied by 2 x 3 x 5 to make it a perfect square.
\therefore120\times2\times3\times5=3600
Hence, the smallest square number which is divisible by 8, 15 and 20 is 3600.
i hope its help you mark as brainlist
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