Question

Find the smallest square number which is divisible by 6, 9 and 15.
Urgent and if needed one can attach the pics showing the process...

Answer 1

I think 72 is the answer

Answer 2

We'll calculate LCM

LCM (6, 9, 15) = 90
2 and 5 not occuring in pair form

But to make it a perfect square, multiply 2 and 5 to 90 (LCM)
90×2×5
900

Required smallest square number is 900

Hope it helped.

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