Question

Find the smallest square number which is divisible by each of the numbers 6,9 and 15

with the LCM shown
more explanations ​

Answer 1

Answer:

900

Step-by-step explanation:

This has to be done in two steps First find the smallest common multiple and than we find the square number.

Least number divisible by each 6,9and 15 with their LCM

In order to get a perfect square each factor of 90 must be paired so, we need make them pair 2 and 5.

Hence, 90 be multiplied by 2×5,i.e.,10.

Therefore,the number needed is 90×10=900

Answer 2

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