Question

Find the smallest square number which is divisible by each of them number 6,9&15

Answer 1

Answer:

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Answer 2

Answer:

LCM of 6,9 and 15=90

by prime factorisation of 90

we get 2×3×3×5 only 3 has its pair

to make it perfect square it must be multiplied by 5×2=10

so, required no. = 90×10= 900