Question

Find the smallest square number which is divisible by each of the numbers 6, 9 and 15​

Answer 1

QUESTION -

Find the smallest square number which is divisible by each of the numbers 6, 9 and 15

ANSWER -

We will first find out the L.C.M of 6, 9 and 15.

L.C.M of 6, 9, 15 = 2 × 3 × 3 × 5 = 2 × 32 × 5 = 90

Since, we need to find the smallest square number divisible by 6, 9 and 15 and in above prime factorization of the numbers we observe that 2 and 5 does not appear in pair, therefore we multiply the L.C.M, 90 by 2 × 5.

Hence,

The required smallest square number = 90 × 2 × 5 = 900.

Answer 2

Answer:

Step-by-step explanation:

Hey there!

Since, we wanted smallest perfect square number divisible by 6, 9 and 15.

So, we calculated LCM by prime factorisation.

LCM = 90

But, 2 and 5 are not in pair.

Therefore, to make it perfect square no. multiply 2 × 5 to LCM (90).

= 90 × 2 × 5

= 90 × 10

= 900

Hence,

Required smallest square no. that's divisible by 6, 9 and 15 = 900

SOLUTION IN THE ABOVE PIC. IS ALSO FOR REFERENCE

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