find the smallest square number which is divisible by each of the number 6 9 15
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Answer:
Required smallest square number is 900
Step-by-step explanation:
Lets calculate LCM
LCM (6, 9, 15) = 90
2 and 5 not occurring in pair form
But to make it a perfect square, multiply 2 and 5 to 90 (LCM)
90×2×5
900
Required smallest square number is 900
Hope it helped
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