find the smallest square number which is divisible by each of the numbers 6 ,9 and 15
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3
Answer:
90
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1
Answer:
we observe that 2 and 5 does not appear in pair, therefore
we multiply
the L.C.M, 90 by 2 × 5.
Hence, The required smallest square number
= 90 × 2 × 5
= 900.
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