Math, asked by sshakshigupta1, 4 months ago

find the smallest square number which is divisible by each of the given number 2 , 14 and 21​

Answers

Answered by Nayan6842
0

Answer:

Basically, you have to find LCM OF 2, 14, 21. Here, I give you a short-cut method. However, you have to be good at numbers. Consider the greatest number 21. 2 can divide it. 14 cannot divide it. Take the next multiple of 21, that is 42. Now, all the three numbers can divide 42 evenly. Therefore, 42 is the least number, which can be divided by 2, 14, 21.

Answered by Anonymous
1

Answer:

1764

Step-by-step explanation:

Prime factors of 2,14 and 21 are

2*2*1

14=2*7

21=3*7

LCM=2*3*7=42

let us make 2*3*7 square

the square=2*2*3*3*7*7

=4*9*49

=36*49

=1764

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