Question

. Find the smallest square number which is divisible by each of the numbers 6, 9 and 15.?
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Answer 1

first find LCM of 6,9 and 15

• LCM of 6,9 and 15 is 3*3*2*5
• LCM is equal to 90
• smallest square number which is divisible by 90 is 900

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Don't write this part I am giving you proof:

smallest square number divisible by 90 is 900 because

90*1=90(it is not a perfect square)

90*2=180(it is not a perfect square)

90*3=270(it is not a perfect square)

90*4=360(it is not a perfect square)

90*5=450(it is not a perfect square)

90*6=540(it is not a perfect square)

90*7=630(it is not a perfect square)

90*8=720(it is not a perfect square)

90*9=810(it is not a perfect square)

90*10=900(it is a perfect square)

so smallest square number which is divisible by 90 is 900.