find the smallest square number which is divisible by each of the numbers 10 15 and 20
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Hence the number 3600 is the smallest square number divisible by each number 8, 15, and 20. Note: LCM of given numbers is exactly divisible by each of the numbers.
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L.C.M. of 8, 15 and 20 is 120. Here, prime factors 2, 3 and 5 have no pair. Therefore 120 must be multiplied by 2 x 3 x 5 to make it a perfect square. Hence, the smallest square number which is divisible by 8, 15 and 20 is 3600.
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