Find the smallest square number which is divisible by each of the numbers 6, 9 and 15. (Please be make sure to write down the whole solution and send me the file of this if you can or write down the method to do it and read the rules on this. Thank You So Much :3) >:D Lol- Ly guys! <3 UnU -w!
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Since, we wanted smallest perfect square number divisible by 6, 9 and 15.
So, we calculated LCM by prime factorisation.
LCM = 90
But, 2 and 5 are not in pair.
Therefore, to make it perfect square no. multiply 2 × 5 to LCM (90).
= 90 × 2 × 5
= 90 × 10
= 900
Hence,
Required smallest square no. that's divisible by 6, 9 and 15 = 900
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