Question

find the smallest square number which is divisible by each of the numbers 6 ,9 and 15

Answer 1

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When we take the LCM,
2 and 5 does not appear in pair, therefore we multiply the L.C.M, 90 by 2 × 5. 
Hence, The required smallest square number = 90 × 2 × 5 = 900.

$\huge\blue{Hope\:it\: helps\: you}$

Answer 2

Answer:

900

Step-by-step explanation:

LCM = 90

=90x2x5 = 900