Question

Find the smallest square number which when divided by 15 or 21 leaves a reminder 4 every time​

Answer 1

LCM of

6 = 2x3

6 = 2x315 = 3x5

6 = 2x315 = 3x518 = 2x3x3

6 = 2x315 = 3x518 = 2x3x3LCM = 2x3x3x5 = 90

6 = 2x315 = 3x518 = 2x3x3LCM = 2x3x3x5 = 905+90 = 95

6 = 2x315 = 3x518 = 2x3x3LCM = 2x3x3x5 = 905+90 = 95The answer is 95.

6 = 2x315 = 3x518 = 2x3x3LCM = 2x3x3x5 = 905+90 = 95The answer is 95.When 95 is divided by 6, 15 or 18, the remainder is 5 in each case.

6 = 2x315 = 3x518 = 2x3x3LCM = 2x3x3x5 = 905+90 = 95The answer is 95.When 95 is divided by 6, 15 or 18, the remainder is 5 in each case.Step-by-step explanation:

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Answer 2

Answer:

answer will be 1

Step-by-step explanation:

a=bq1+r

15=bq1+4

bq1=11

a=bq2+r

21=bq2+4

bq2=17

then find HCF of 11 and 17.

and it is 1

therefore answer is will be 1