Find the smallest square numbers which is divisible by each of the numbers 6,9and15
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3
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BECAUSE WE WANT THE SMALLEST SQUARE NUMBER WE HAVE TO TAKE THE LCM OUT.
THE LCM WILL BE
6=2×3
9=3×3×3
15=5×3
In the above prime factorisation we can see that 5 and 2 are not in a pair. So as to get the smallest square we need to multiply 90 by 2 and 5.
Thus,
90×2×5=900
900 will be the smallest square no. divisible by 6, 9 & 15
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