Question

Find the smallest square numbers which is divisible by each of the numbers 6,9and15​

Answer 1

Answer:

3

Step-by-step explanation:

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Answer 2

Answer:

BECAUSE WE WANT THE SMALLEST SQUARE NUMBER WE HAVE TO TAKE THE LCM OUT.

THE LCM WILL BE

6=2×3

9=3×3×3

15=5×3

In the above prime factorisation we can see that 5 and 2 are not in a pair. So as to get the smallest square we need to multiply 90 by 2 and 5.

Thus,

90×2×5=900

900 will be the smallest square no. divisible by 6, 9 & 15