Question

find the smallest value of integer m such that the function f(x)=mx2+7x+3 is always positive for all real values of x.​

Answer 1

Step-by-step explanation:

divisible by 4 is at least 4, at most three of the nine numbers are divisible by 4. ... The constant function f (x) = k, where k is a positive integer, is the only possible ... In general, F(x) is nonnegative for all real.

Answer 2

Answer:

Step-by-step explanation:

f two positive numbers is always positive, i.e., if x ≥ 0 and y ≥ 0, then ... this shows that the square of any real number is non-negaitive. ... Let m be the smallest integer such that na < m. ... 3. Solution. a) The function f is bi- jection since f(x) < f(y) for any pair x, y ∈ R with ... for every q ∈ Q. Prove that f(x)=0 for every x ∈ R.

Missing: mx2+ ‎| Must include: mx2+