Find the smallest value of k such that 54k is a perfect square.
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Answered by
3
Answer:
any number whose sum of digits is divible by 9 must itself be divisible by 9. if we add the digits of the number we get 1+5+7+5=18 which is a multiple of 9 so it must be divisible by 9. therefore k must be equal to 7 to make it a perfect square. hence 7 is the smallest number to make it a perfect square.
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6
Answer:
54 = 2*3*3*3
k = 2*3 =6
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