find the smallest value of n such that the lcm of n and 15 is 45
Answers
Answered by
1
Answer:
3
Step-by-step explanation
Answered by
8
Answer:
The smallest value of n such that the LCM of n and 15 is 45.
The prime factors of 15 are
15 = 3 x 5
So in LCM of n and 15 , we must include both the prime factors and the LCM is 45.
Since 3 is one time in the prime factor of 15. But to make 45 we need one more 3 and its possible if we take the value of n as below"
n=9
9 = 3 x 3 = 3²
Hence the LCM will be
3² x 5 = 45
Hence the smallest possible value of n is 9.
MARK AS BRAINLIEST
PLZ FOLLOW ME
Similar questions