Find the smallest value of n such that the LCM of n and 6 is 24.
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thanks for freee points
Step-by-step explanation:6 = 2 ⋅ 3, 24 = 2³ ⋅ 3. Now, the least common multiple of 6 and some number n needs to yield a prime factorization of 2³ ⋅ 3. ... So, in this case, we need n to have 3 factors of 2 and up to 1 factor of 3. This implies that there are 2 such integers n that will work.
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