Question

find the smallest value of the unknown digit x such that the number will be divisible by 3. a) 4526x. b) 213x6​

Answer 1

Step-by-step explanation:

Question :

find the smallest value of the unknown digit x such that the number will be divisible by 3.

Given numbers :

a) 4526x

b) 213x6

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Answer :

Divisibilty rule of 3 : A number is said to be divisible by 3 if the sum of all digits of that number is divisible by 3.

a. 4526x = 4 + 5 + 2 + 6 = 17.

Here we get the number 17 but it is not divisible by 3.

So to get divisible by 3, we will add 1 to it.

4526x = 4 + 5 + 2 + 6 + 1 = 18

$\bf{as \: 18 \: is \: divisible \: by \: 3,}$

$\bf\red{so, \: x \: = 1}$

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b. 213x6 = 2 + 1 + 3 + 6 = 12

Here we get the number 12 which is divisible by 3.

Therefore, we will add 0 to it.

213x6 = 2 + 1 + 3 + 0 + 6 = 12

$\bf{as \: 12 \: is \: divisible \: by \: 3,}$

$\bf\red{so, \: x \: = 0}$

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$\huge\fcolorbox{red}{blue}{More Info-:}$

Divisibilty rule of 2 - If a number ends in a 0, 2, 4, 6 or 8, it is divisible by 2. All even numbers, by definition, are divisible by 2.

Divisiblity rule of 4 - if the number formed by the last two digits in a number is divisible by 4, the original number is divisible by 4.

Divisiblity rule of 5 - If the last number is either 0 or 5, the entire number is divisible by 5.

Divisiblity rule of 6 - A large number is divisible by 6 if it is divisible by the numbers 2 and 3 both.