Question

find the smallest value of x for each of the given numbers to be divisible by 11. 1)46x6. 2)3x74.​

Answer 1

Answer:

see the attachment hope it helped you

Answer 2

$\sf{\:}$$\sf\green{Question:-}$$\sf{\:}$

find the smallest value of x for each of the given numbers to be divisible by 11. 1)46x6. 2)3x74.

$\sf{\:}$$\sf\green{Answer:-}$$\sf{\:}$

A):- 7

B):-

solution:-

first, divisibility of 11 =

A number divisible by 11, if the difference of the sum of digit of odd place and the sum of an digit at even places is either zero or divisible by 11

A) so , 46x6

4 + 6 + x + 6 in this 4 and x are odd

4 + x. - 6 + 6

4 + x

so, 11 - 4

x = 7 $\sf{\:}$$\sf\green{❥❥ᴀ᭄ɴsᴡᴇʀ࿐}$$\sf{\:}$

B) so , 3x74

3 + x + 7 + 4 in this 3 and 7 are odd

3 + 7 - x + 4

10 - x + 4

6 + x

so, 11 - 6

x= 5 $\sf{\:}$$\sf\green{❥❥ᴀ᭄ɴsᴡᴇʀ࿐}$$\sf{\:}$