Question

find the smallest value of x for which 3141X1 is divisabile by 3

Answer 1

Answer:2

Step-by-step explanation:

For a number to be divisible by 3, the sum of the digits should be a multiple of 3.

we have sum of digits= 3+1+4+1+x+1 = 10+x

The smallest number of x to give a multiple of 3 is 2 (∵10+2=12, a multiple of 3)

Answer 2

Answer:

hope it will help you:-)