Find the smallest value of x for which 3141X1 is divisible by 3
Answers
Answered by
9
Answer:
2
Step-by-step explanation:
3+1+4+1+x+1=divisible by 3
10+x=divisible by 3
10+2=divisible by 3
x=2
Answered by
1
Answer:
2
Step-by-step explanation:
value of x is 2
3141x1 divisible by 3 only if sum of digits of the num should be divisible by 3
the sum digit is 10 +x
the smallest value of x to become number divisible by 3 is 2
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