Question

Find the smallest value of x such that the LCM (Lowest common multiple) of x and 15 is 45.

Answer 1

Smallest value of x such that the LCM of x and 15 is 45.

Step 1: Prime factorization of 45:

45 →9 * 5 →3 * 3 * 5

Step 2: LCM of 15 and 3 = 15

Step 3: LCM of 15 and 5 = 15

Step 4: LCM of 15 and 9 = 45

smallest value of x such that LCM of X and 15 is 45. therefore the smallest value is 9.