Math, asked by sk9431371, 1 month ago

Find the smallest which when devided by 14 and 21 leaves no remainder.​

Answers

Answered by aparna4738
1

Answer:

21 = 3x7

14 = 2x7

LCM = 2x3x7 = 42.

The smallest number is 42 which when divided by 14 and 21 leaves no remainder.

Answered by Anonymous
0

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