Question

find the smallest whole number which is exactly divisible by3/2,4/3, 9/4, 7/2, 21/5​

Answer 1

Answer:

252

Step-by-step explanation:

if X is that number

x/(3/2) must be a whole no.

therefore X*2/3 must be a whole no.

so X must be exactly divisible by 3 only

similarly X must be exactly divisible by 3,4,9,7,21

so minimum prime factors needed are 3,3,2,2,7 only

therefore answer is 3*3*2*2*7=252

Answer 2

Step-by-step explanation:

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