Find the smallet numbe by which
08 wt be mutiplied obtain a perfect cube
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Prime factorising 2808, we get,
2808=2×2×2×3×3×3×13
=2³×3³×13¹
We know, a perfect cube has multiples of 3 as powers of prime factors.
Here, number of 2's is 3, number of 3's is 3 and number of 13's is 1.
So we need to multiply another 13² to the factorization to make 2808 a perfect cube.
Hence, the smallest number by which 2808 must be multiplied to obtain a perfect cube is 13² =169.
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