Math, asked by sanjeevanishewale166, 8 months ago

find the Sn for the GP: 2, -2, 2, -2.​

Answers

Answered by pulakmath007
42

SOLUTION

TO DETERMINE

 \sf{The  \: S_n  \: for \:  the \:  GP \:  \:  \:  2,-2,2,-2,.....}

FORMULA TO BE IMPLEMENTED

If in a Geometric Progression

First term = a and common ratio = r then

The Sum of the first n terms

 \displaystyle \sf {S_n  = a \times  \frac{ {r}^{n} - 1 }{r - 1}  } \:  \:  \: when \:  \: r > 1

 \displaystyle \sf {S_n  = a \times  \frac{ 1 - {r}^{n}  }{1 - r}  } \:  \:  \: when \:  \: r  < 1

EVALUATION

Here the given Geometric Progression is

2 , - 2 , 2 , - 2 , ........

First term = a = 2

Common Ratio = r = - 1 ( < 1 )

Hence the required sum of first n terms

 \displaystyle \sf {S_n  = 2 \times  \frac{ 1 - {( - 1)}^{n}  }{1 - ( - 1)}  }

 \implies \displaystyle \sf {S_n  = 2 \times  \frac{ 1 - {( - 1)}^{n}  }{2}  }

 \implies \displaystyle \sf {S_n  =  1 - {( - 1)}^{n}  }

FINAL ANSWER

 \boxed{\displaystyle \sf { \:  \: S_n  =  1 - {( - 1)}^{n} \:   }}

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