Question

Find the solubility of KNO3 at 20°C when the mass
of the empty dish is 50 g, the mass of dish and
solution is 65 g, while the mass of dish and residue is 54.3 g

(b) What weight of sodium nitrate will separate
when
a saturated solution containing 50 gram of water
is cooled from 50°C to 30°C ? The solubility of
NaNO3 at 50°C and 30°C is 114 g and 86 g
respectively.
​

Answer 1

Answer:

(a) Mass of solution = (mass of dish and solution)−(mass of dish ) =65g−50g=15g

Mass of solute = (mass of dish and residue )−(mass of dish) = 54.3g−50g=4.3g

Mass of solvent = mass of solution - mass of solute =15−4.3=10.7g

Solubility is amount of solute present in 100g of solvent.

Hence, 4.3g of solute is dissolved in 110.7g solvent.

1g solvent will dissolve 4.3/10.7g solute.

100g of solvent will dissolve (4.3×100)/10.7=40.17g of solute.

(b) 43 grams

Answer. hence, or solution of 50g water= 86/2 = 43 grams of NaNO3. Hence, when a saturated solution of sodium nitrate at 30°C is left to cool, then 43 grams of solid sodium nitrate will separate out.

Answer 2

Answer:

the above answer is the correct one

Explanation:

follow that answer only