Question

Find the solution (a) 3t - 4 = 11 (b) 3p + 2p + 4p = 45​

Answer 1

Answer:

Solution :-

(a) 3t - 4 = 11

➩ 3t = 11 + 4

➩ 3t = 15

➩ t = 15/3

➩ t = 5

∴ The answer of this question is 5

b) 3p + 2p + 4p = 45

➩ 5p + 4p = 45

➩ 9p = 45

➩ p = 45/9

➩ p = 5

∴ The answer of this question is 5

Answer 2

Answer:

We will get the value (a) t=5 and (b) p=5

Step-by-step explanation:

• As per the question we have to evaluate the given data.

              Given data:- (a)3t-4=11,   (b)3p+2p+4p=45

              To find:- Value of (a)3t-4=11,   (b)3p+2p+4p=45

              Solution:-

• Here we will use the transposition method.

• Transposition is one of the linear equations.

• To solve the transposition method we will Identify the variables and constants.

• Then we Simplify the equation in LHS and RHS.

• Now Simplify the equation using arithmetic operations.

           $(a)3t-4=11\\=>3t-4=11\\=>3t=11+4\\=>3t=15\\=>t=\frac{15}{3}\\=>t=5$

           $(b)3p+2p+4p=45\\=>3p+2p+4p=45\\=>9p=45\\=>p=\frac{45}{9} \\=>p=5$