Find the solution a) z + 6= 13 , b) 10 y = 30
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a- z=13-6=7
b-y=30/10=3
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This is can basic sum of algebra
- First sum Transposing 6 to other side we get -6. Hence z=13-6=7 Hence z is 7
- Here to get the value of y we must divide 30 by 10 Hence y=30/10 therefore y=3
- Hope it helps Mark me as brainliest
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