Math, asked by kalagiri123456, 10 months ago

find the solution............for 20pt.​

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Answered by kamalveer178
0

Answer:

x^2 + 1 = 0

x^2=-1

x = root 1

x =1

p ( x ) = x^4+x^3+8x^2+ax+ b

p (x) = (1)^4+(1)^3+8 (1)^2+a (1)+b

= 1+1+8+a+b

0=10+a+b

-10=a+b

-10-b=a. ( let it be equation 1 )

p ( x ) = x^4+x^3+8x^2+ax+ b

p (x) = (1)^4+(1)^3+8(1)^2+a (1)+b

0= 1+1+8+a+b

0=10+(-10-b)+b. ( from eq. 1 )

0=10-10-b+b

0=b put it in eq.1

-10-0=a

10=a

Answered by Abhis506
1

Answer:

x^2 + 1 = 0

x^2=-1

x = root 1

x =1

p ( x ) = x^4+x^3+8x^2+ax+ b

p (x) = (1)^4+(1)^3+8 (1)^2+a (1)+b

= 1+1+8+a+b

0=10+a+b

-10=a+b

-10-b=a. ( let it be equation 1 )

p ( x ) = x^4+x^3+8x^2+ax+ b

p (x) = (1)^4+(1)^3+8(1)^2+a (1)+b

0= 1+1+8+a+b

0=10+(-10-b)+b. ( from eq. 1 )

0=10-10-b+b

0=b put it in eq.1

-10-0=a

10=a

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