find the solution............for 20pt.
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Answer:
x^2 + 1 = 0
x^2=-1
x = root 1
x =1
p ( x ) = x^4+x^3+8x^2+ax+ b
p (x) = (1)^4+(1)^3+8 (1)^2+a (1)+b
= 1+1+8+a+b
0=10+a+b
-10=a+b
-10-b=a. ( let it be equation 1 )
p ( x ) = x^4+x^3+8x^2+ax+ b
p (x) = (1)^4+(1)^3+8(1)^2+a (1)+b
0= 1+1+8+a+b
0=10+(-10-b)+b. ( from eq. 1 )
0=10-10-b+b
0=b put it in eq.1
-10-0=a
10=a
Answered by
1
Answer:
x^2 + 1 = 0
x^2=-1
x = root 1
x =1
p ( x ) = x^4+x^3+8x^2+ax+ b
p (x) = (1)^4+(1)^3+8 (1)^2+a (1)+b
= 1+1+8+a+b
0=10+a+b
-10=a+b
-10-b=a. ( let it be equation 1 )
p ( x ) = x^4+x^3+8x^2+ax+ b
p (x) = (1)^4+(1)^3+8(1)^2+a (1)+b
0= 1+1+8+a+b
0=10+(-10-b)+b. ( from eq. 1 )
0=10-10-b+b
0=b put it in eq.1
-10-0=a
10=a
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