Find the solution for n/3 n by 3
= 4
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Answer:
3n
3
+4n
2
+n=0
⇒n[3n
2
+4n+1]=0
⇒3n
2
+4n+1=0 n=0
⇒3n
2
+3n+n+1=0
⇒3n[n+1]+1[n+1]=0
⇒(n+1)(3n+1)=0
⇒ n=-1 or 3n=-1
⇒ n=-1 or n=−
3
1
∴n=0,−1,−
3
1
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