Question

find the solution for the following equation 4x²-4x+1=0​

Answer 1

Answer:

$4{x}^{2} - 4x + 1 \\ \\ 4 {x}^{2} - (2 + 2)x + 1 \\ \\ 4 {x}^{2} - 2x - 2x + 1 \\ \\ 2x(2x - 1) - 1(2x - 1) \\ \\ (2x - 1)(2x - 1)$

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Answer 2

Answer:

1/2 and 1/2

Step-by-step explanation:

4x² - 4x + 1 = 0

=> 4x² - 2x - 2x + 1 = 0

=> 2x( 2x - 1 ) - 1( 2x - 1 ) = 0

=> ( 2x - 1 )( 2x - 1 ) = 0

=> 2x - 1 = 0 or 2x - 1 = 0

=> 2x = 1 or 2x = 1

=> x = 1/2 or x = 1/2

Hence 1/2 and 1/2 are the solutions