Question

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Answer 1

$\large\blue{\underline{\boxed{\red{\bf{\hookrightarrow SolutioN:-}}}}}$

[ For figure refer to attachment : ]

➳Before we proceed , things we should know is -

❒ Displacement :-

➤ The shortest distance between initial and final point is called displacement. it is a vector quantity and thus calculated using vector law of addition .

❒ Average velocity :-

➤ Total displacement covered per unit time is called average velocity.

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Here , we can see that

• Total time taken = 50s .
• Displacement = ? .

Lets find displacement :

Here we can see that from the figure see that the persons's displacement will be equal to AF .

Now , EH = HD + DE = 5m + 3m = 8m .

And , EH = AG = 8m .

Also , here EF = 4m & AH = EG =(4-2)m = 2m .

So , GF = EF - EG = 4m - 2m = 2m.

So , now in ∆AGF , measure of AF will be Displacement .

$\tt:\implies Hypontenuse^2=perpendicular^2+base^2$

$\tt:\implies AF^2=GA^2+GF^2$

$\tt:\implies AF^2 =8m^2+2m^2$

$\tt:\implies AF^2=64m^2+4m^2$

$\tt:\implies AF^2=68m^2$

$\underline{\boxed{\red{\tt{\longmapsto \:\:AF\:\:=\:\:8.24m}}}}$

Now , average velocity can be calculated by ,

$\large\orange{\underline{\boxed{\purple{\tt{\dag Velocity_{average}\:\:=\:\:\dfrac{Total\: Displacement}{Total\:time}}}}}}$

$\tt:\implies Velocity_{avg.}=\dfrac{Total\: Displacement}{Total\:time}$

$\tt:\implies Velocity_{avg.}=\dfrac{8.24m}{50s}$

$\tt:\implies Velocity_{avg.}=\dfrac{824}{50\times100}$

$\underline{\boxed{\red{\tt{\longmapsto \:\: Velocity_{avg.}\:\:=\:\:0.164m/s}}}}$

$\blue{\boxed{\red{\bf{\dag\:Hence\:the\: average\: velocity\:is\:0.164ms^{-1}.}}}}$