Question

find the solution for y^2 - (13/2) y - (7/2) = 0​

Answer 1

I hope you helped.

take the lcm and add all the terms in equation and solve it.

Answer 2

Answer:

{7 , -1/2}

Step-by-step explanation:

$y^2 - (13/2) y - (7/2) = 0$

$\to 2y^2 - 13 y - 7 = 0$

$\to y = \frac{13 \pm \sqrt{13^2-4\times2\times(-7)} }{2\times2} = \frac{13 \pm \sqrt{225} }{4}=\frac{13 \pm15}{4}$

\to y ={28/4 , -2/4} = {7 , -1/2}