Question

find the solution of 2 power 8* 4 power -4
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Answer 1

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Answer 2

${2}^{8} \times {4}^{ - 4}$

${4}^{ - 4} can \: be \: written \: as \: {2}^{2 \times - 4} = {2}^{ - 8}$

This • sign between the numbers means multiplication

So, Using the identity

${a}^{m} \times {a}^{n} = {a}^{m + n}$

So, the solution will be

${2}^{8} \times 2 {}^{ - 8}$

$2 {}^{8 + ( - 8)}$

$= 2 {}^{8 - 8}$

$= {2}^{0}$

Now we know that any number with power 0 is equal to 1

So,

${2}^{0 } = 1$

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