find the solution of 3x-2y=20, x+3y=14.
Answers
Answer:
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Step-by-step explanation:
Given: 2x−3y=−14...(1)
3x−2y=−6...(2)
After adding (1) and (2) equations. we get
2x−3y+3x−2y=−14−6
⇒5x−5y=−20⇒x−y=−4...(3)
On subtracting (1) from (2). we get
3x−2y−2x+3y=−6+14
⇒x+y=8...(4)
Now adding (3) and (4). we get
2x=4⇒x=2
By putting x=2 in (3), we get
2−y=−4⇒y=6
∴(2,6) is solution of given equations.
Value of xy=2×6=12.
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Answer:
Given⤵
➡3x-2y= 20 and x+3y = 14.
To find⤵
➡Solution of equation.
Solution⤵
⚫Let the equation
3x-2y=20 ...(i)
x+3y=14 ...(ii)
⚫Multiply by 3 in equation (ii), we get
3x+9y=42 .... (iii)
⚫Subtracting equation (i) from (iii), we get
3x+9y=42
3x-2y=20
- + -
__________
11y=22
y= 22/11
y= 2
⚫Now substituting value y= 2 in equation (i) , we get
➡3x-2×2=20
➡3x-4=20
➡3x=20+4
➡3x=24
➡x=24/3
➡x=8
✅Hence, the solution is x=8 and y= 2 or (8, 2).
Verification⤵
➡3x-2y= 20 and x+3y= 14
⚫Substituting the value of x=8 and y=2, we get
➡3×8-2×2=20 and 8+3×2=14
➡24-4=20 and 8+6=14
➡20=20 and 14=14
LHS=RHS LHS=RHS
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