find the solution of 5x+3y=12 and 15x+9y=15
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Answered by
4
Step-by-step explanation:
5x+3y=12
substitute 3y in both places
5x+3y-3y=12-3y
5x=12-3y
now divide each side by 5
5x/5=12/5-3y/5
x=2.4+ -0.6y
Answered by
2
5x+3y=12
5x=12-3y
X=12-3y/5
and in second equation
15x+9y=15
15(12-3y/5)+9y=15
180-75y/5+9y=15
taking LCM of 1 and 5
180-75y+45y/5=15
180-30y/5=15
taking 5 common
5(36-6y)/5 = 15
36-6y =15
36-15=6y
21=6y
3.5=y
since y=3.5
substituting value in equation one
5x+3(3.5)=12
5x+10.5=12
5x=12-10.5
5x=1.5
X=0.3
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