Find the solution of equation
log(x+1)+log(x+3)=1
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Heya....!!!
First of all we will find Domain
Domain :: x+1 >0
log(x^2+4x+3) = 1
so ,, x^2+4x+3 =1
x can be = 0 , -4
x = -4 is not in domain .
solution = x =0 .
HOPE IT HELPSU
First of all we will find Domain
Domain :: x+1 >0
log(x^2+4x+3) = 1
so ,, x^2+4x+3 =1
x can be = 0 , -4
x = -4 is not in domain .
solution = x =0 .
HOPE IT HELPSU
Anonymous:
Thnx bro
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