Question

find the solution of following equation (x+2)(x+3)=0​

Answer 1

Answer:

How do I solve Algebra Equation (x+2) (x+3)=0?

This is a quadratic equation. Normally, you'll probably be given something that looks like x^2 + 2x - 5 = 0. Then you'd have to factor the equation to solve. Here, you're lucky - it's already factored! That means we just need to set each of the two parts equal to zero, and solve each part. Remember you can have 2 answers to a quadratic equation!

(x-2)(x+3) = 0

(x-2) = 0 OR (x+3)=0

x-2+2 = 0+2 OR x+3-3 = 0-3

x = 2 OR x = -3

this is already factored. use the zero product rule: if ab=0, then a=0, and b=0

therefore, if (x+2)(x+3)=0, let x+2=0, subtract 2 from each side, and x+2-2 = 0-2, and x = -2

then let the other factor equal 0: let x+3 =0, subtract 3 from each side, x+3-3 = 0-3 and. x = -3

therefore x = -2, and. x = -3

or

(x+2)(x+3) - Original Equation

x^2 + 2x +3x + 6 - FOIL

x^2+5x+6 - Answer

If you are solving for X you have to isolate each factor and set it equal to 0

Solve the factor of (X+2) first

x+2=0

(x+2) -2= 0-2 subtract 2 from both sides

x = -2 answer

Now solve the factor of (x+3)

(x+3) = 0

x+3-3= 0-3 subtract 3 from both sides

x = -3 Answer

From the calculations, you can see that x= -2 and -3.

Step-by-step explanation:

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Answer 2

Answer:

First the case of x+2 = 0

Then on changing the side of 2 it will become -2

Then equation will be

x = 0-2

x = -2

Similarly the second case

x+3 = 0

x = 0-3

x = -3

Now we have two answers, until you are given any condition of answer we will write both as our answers

So x = -2,-3

Hope it helps!!