Question

Find the solution of simultaneous equations x+3y = 14 and x-2y =20​

Answer 1

Answer:

$x = 19 \frac{3}{5} \:$

$y = - 1\frac{1}{5}$

Step-by-step explanation:

$x + 3y = 14 \: \: \: \: - - - - 1\\ x - 2y = 20 \: \: \: \: - - - - 2$

$5y = - 6 \\ or \: y = - \frac{6}{5} \\ or \: y = - 1 \frac{1}{5}$

$x + 3 \times ( - \frac{6}{5} ) = 14 \\ or \: x - \frac{18}{5} = 14 \\ or \: x = 14 + \frac{18}{5} \\ or \: x = \frac{70 + 18}{5} \\ or \: x = \frac{88}{5} \\ or \: x = 19 \frac{3}{5}$

Answer 2

Step-by-step explanation:

2x−3y=−14...(1)

              3x−2y=−6...(2)

After adding (1) and (2) equations. we get

2x−3y+3x−2y=−14−6

⇒5x−5y=−20⇒x−y=−4...(3)

On subtracting (1) from (2). we get

3x−2y−2x+3y=−6+14

⇒x+y=8...(4)

Now adding (3) and (4). we get

2x=4⇒x=2

By putting x=2 in (3), we get

2−y=−4⇒y=6

∴(2,6) is solution of given equations.

Value of xy=2×6=12.