Question

find the solution of the differential equation p2+y2=1​

Answer 1

The Solution of the differential equation p2+y2=1​ is y = 2p + $\frac{1}{2}$

Given that;

p2+y2=1​

To find;

The Solution of the differential equation p2+y2=1​

Solution;

It is given that,

p2 + y2 = 1

p.2 + y.2 = 1

p.2 = 1 - y.2

dividing the above equation by 2 on both sides we get,

p2/2 = 1/2 - y2/2

p = 1 - 2y/2 or,

y = 2p + $\frac{1}{2}$

Hence, The Solution of the differential equation p2+y2=1​ is y = 2p + $\frac{1}{2}$

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